128x^2-72=0

Solution for 128x^2-72=0 equation:

128x^2-72=0

a = 128; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·128·(-72)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192}{2*128}=\frac{-192}{256}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192}{2*128}=\frac{192}{256}
=3/4
$